What mass of acetaldehyde can be obtained from 44.8 m ^ 3 acetylene at 90% yield?

1.Let’s find the amount of acetylene substance.

The volume is determined by the formula:

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

From here we derive the formula for the amount of substance.

n = V: Vn.

n = 44.8 m3: 22.4 kg / kmol = 2 kmol.

2. Let’s compose the reaction equation, find the quantitative relations of substances.

НС ≡СН + НОН → Н3С – СОН.

1 mole of acetylene accounts for 1 mole of aldehyde. The substances are in quantitative ratios of 1: 1. The amounts of acetylene and aldehyde will be the same.

n (С2 Н2) = n (Н3С – СОН) = 2 kmol.

Let’s find the mass of the aldehyde by the formula:

m = n × M,

М (Н3С – СОН) = 44 kg / kmol.

m = 44 kg / kmol × 2 kmol = 88 kg.

88 kg of aldehyde should be obtained according to calculations. But according to the condition of the problem, the yield of aldehyde is 90%.

Let us find the output of the aldehyde according to the condition of the problem.

88 g – 100%,

X – 90%,

X = (88 g × 90%): 100% = 79.2 kg.

Answer: 79.2 kg.