What mass of acetic acid ethyl ester can be obtained from 120 g of acetic acid and ethanol?

1. Let’s write down the reaction equation:

CH3COOH + C2H5OH = CH3COO-C2H5 + H2O.

2. Find the amount of acetic acid:

n (CH3COOH) = m (CH3COOH) / M (CH3COOH) = 120 g / 60 g / mol = 2 mol.

3. According to the reaction equation, we find the quantity and then the mass of the ether:

n (CH3COO-C2H5) = n (CH3COOH) = 2 mol.

m (CH3COO-C2H5) = n (CH3COO-C2H5) * M (CH3COO-C2H5) = 2 mol * 88 g / mol = 176 g.

Answer: m (CH3COO-C2H5) = 176 g.



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