What mass of air is required to fill the inner tube in a car tire if its volume is 12 liters?

What mass of air is required to fill the inner tube in a car tire if its volume is 12 liters? the chamber is pumped at a temperature of 27 s to a pressure of 2.2 * 10 ^ 5

M = 0.029 kg / mol.
V = 12 L = 12 * 10 ^ -3 m ^ 3.
T = 300 K.
P = 2.5 * 10 ^ 5 Pa.
R = 8.31 J / mol * K.
m -?
Let’s use the Mendeleev-Cliperon equation for gas: P * V = m * R * T / M, where P is the gas pressure, V is the gas volume, m is the gas mass, R is the universal gas constant, T is the absolute temperature, M is the molar weight.
m = P * V * M / R * T.
m = 2.5 * 10 ^ 5 Pa * 12 * 10 ^ -3 m ^ 3 * 0.029 kg / mol / 8.31 J / mol * K * 300 K = 0.035 kg.
Answer: the mass of air in a car tire is m = 0.035 kg.