What mass of alabaster will be obtained by calcining (160 ° C) 1 ton of natural gypsum containing 14% impurities?
| September 7, 2021 | education
Solution:
M (СaSО4 * 2H2О) = 136 + 2 * 18 = 172 kg / kmol –
molar mass of gypsum,
M (CaSO4 * 0.5H2O) = 136 +9 = 145 kg / lmol –
molar mass of alabaster
m (CaSO4 * 0.5H2O) = 145 * 1000 * 0.86 / 172 = 725 kg
Answer: 725 kg
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