What mass of aluminum chloride is formed by the interaction of hydrochloric acid

What mass of aluminum chloride is formed by the interaction of hydrochloric acid with 337.5 kg of technical aluminum with 80% pure aluminum?

1. We make a chemical equation, not forgetting to put down the coefficients:

2AL + 6HCI = 2AICI3 + 3H2.

2. Let’s find the mass of pure aluminum:

m (Al) = 337.5 * 80/100 = 270 kg (in the equation m (Al) = 2 * 270 = 540 kg).

3. Find the mass of aluminum chloride:

m (AICI3) = 2 * (27 + 35.5 * 3) = 267kg.

4.Using the equation, make up the proportion and solve it:

270/54 = X / 267;

X = 270 * 267/540 = 133.5 kg.

Answer: m (AICI3) = 133.5 kg.