What mass of aluminum hydroxide falls out after merging the aluminum chloride solution

What mass of aluminum hydroxide falls out after merging the aluminum chloride solution with 200 grams of 12% sodium hydroxide solution.

AlCl3 + 3NaOH = 3NaCl + Al (OH) 3.
1) Find the mass of the sodium hydroxide solute. To do this, we multiply the mass fraction of the substance by the mass of the solution and divide by one hundred percent: 200 * 12/100 = 24g.
2) Molar mass of sodium hydroxide: 23 + 1 + 16 = 40.
3) The amount of sodium hydroxide substance: 24/40 = 0.6 mol.
4) According to the reaction equation, there is one mole of aluminum hydroxide for three moles of sodium hydroxide. This means that the amount of aluminum hydroxide substance is: 0.6 * 3 = 1.8 mol.
5) Mass of aluminum hydroxide: 1.8 * (27 + 48 + 3) = 140.4 g – answer.