What mass of aluminum is required to obtain 2.24 liters? hydrogen in a reaction with hydrochloric acid?

Aluminum reacts with hydrochloric acid. This forms an aluminum chloride salt and elemental hydrogen is released. The interaction is described by the following chemical equation.

Al + 3HCl = AlCl3 + 3/2 H2;

Let’s calculate the chemical amount of the released hydrogen gas.

For this purpose, we find the ratio of its volume to the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).

N H2 = 2.24 / 22.4 = 0.1 mol;

To obtain such an amount of hydrogen, it is necessary to dissolve 0.1 x 2/3 = 0.0666 mol of aluminum.

Let’s calculate its mass.

M Al = 27 grams / mol;

m Al = 27 x 0.0666 = 1.798 grams;