What mass of aluminum is required to reduce 0.4 mol of iron (III) oxide?

univerkov | May 8, 2021 | education

Let’s write down the reaction equation and arrange the coefficients:
2Al + Fe2O3 = Al2O3 + 2Fe
According to the equation, 1 iron oxide salt requires 2 power of aluminum.
Hence 0.8 mol of aluminum.
Weight = 0.8 * 27 = 21.6g

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