What mass of aluminum oxide can be obtained by the interaction of oxygen and 0.5 mol of aluminum.

1. The interaction of aluminum with oxygen describes the reaction:

4Al + 3O2 = 2Al2O3;

2.Set the chemical amount of aluminum oxide:

n (Al2O3) = n (Al): 2 = 0.5: 2 = 0.25 mol;

3.Calculate the mass of the resulting oxide:

m (Al2O3) = n (Al2O3) * M (Al2O3);

M (Al2O3) = 2 * 27 + 3 * 16 = 102 g / mol;

m (Al2O3) = 0.25 * 102 = 25.5 g.

Answer: 25.5 g.