What mass of aluminum oxide can interact with 200 g of sulfuric acid solution with 10% mass fraction of acid.

1. The interaction of aluminum oxide with sulfuric acid proceeds according to the equation:
Al2O3 + 3H2SO4 = Al2 (SO4) 3 + 3H2O;
2.calculate the mass of sulfuric acid:
m (H2SO4) = w (H2SO4) * m (solution) = 0.1 * 200 = 20 g;
3. find the chemical amount of sulfuric acid:
n (H2SO4) = m (H2SO4): M (H2SO4);
M (H2SO4) = 2 + 32 + 4 * 16 = 98 g / mol;
n (H2SO4) = 20: 98 = 0.2041 mol;
4.determine the amount of aluminum oxide:
n (Al2O3) = n (H2SO4): 3 = 0.2041: 3 = 0.068 mol;
5.Calculate the mass of the oxide:
m (Al2O3) = n (Al2O3) * M (Al2O3);
M (Al2O3) = 2 * 27 + 3 * 16 = 102 g / mol;
m (Al2O3) = 0.068 * 102 = 6.936 g.
Answer: 6.936 g.