What mass of aluminum will react with 49 g of 1% sulfuric acid solution?

Let’s make a chemical equation: 2Al + 3H2SO4 = Al2 (SO4) 3 + 3H2.
Let’s find the mass of H2SO4: m (H2SO4) = m (solution) * ω = 49 * 0.01 = 0.49g.
Let’s find the amount of substance H2SO4: n (H2SO4) = m / M = 0.49 / 98 = 0.005 mol.
To find out the amount of aluminum substance, we make up the proportion:
n (Al) = X / 2 = 0.005 / 3;

X = 0.0033 mol.

We find the mass of aluminum: m (Al) = n * M = 0.0033 * 27 = 0.0891g.

Answer: m (Al) = 0.0891g.