What mass of ammonium chloride is formed by the interaction of hydrogen chloride with ammonia weighing 5.1 g

What mass of ammonium chloride is formed by the interaction of hydrogen chloride with ammonia weighing 5.1 g, if the reaction proceeds according to the following process: NH3 + HCl- NH4Cl

1. According to the reaction equation:

NH3 + HCl = NH4Cl

all substances are taken in an amount of 1 mol.

Find the molar masses of ammonia (NH3) and ammonium chloride (NH4Cl) by the formula:

M (NH3) = n * M = 1 mol * (14 + 1 * 3) = 17 g / mol

M (NH4Cl) = n * M = 1 mol * (14 + 1 * 4 + 35.5) = 53.5 g / mol

2. Let’s calculate the mass of ammonium chloride, making up the proportion:

5.1 g NH3 – x g NH4Cl

17 g NH3 – 53.5 g NH4Cl

Hence, x = 5.1 * 53.5 / 17 = 16.05 g.