What mass of ammonium sulfate is formed by the interaction of ammonia with 40 g of 80% sulfuric acid solution?

Ammonia reacts with sulfuric acid. This synthesizes the ammonium sulfate salt.

This reaction proceeds according to the following chemical reaction equation:

2NH3 + H2SO4 = (NH4) 2SO4;

Let’s find the chemical amount of sulfuric acid. For this purpose, we divide its weight by its molar mass.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 40 x 0.8 / 98 = 0.3265 mol;

The same amount of ammonium sulfate will be synthesized.

Let’s determine its weight.

To do this, we multiply the chemical (molar) amount of a substance by its molar (atomic) mass.

M (NH4) 2SO4 = (14 + 4) x 2 + 32 + 16 x 4 = 132 grams / mol;

The weight of ammonium sulfate will be:

m (NH4) 2SO4 = 132 x 0.3265 = 43.098 grams;