What mass of aniline can be obtained from nitrobenzene weighing 369 g. if the mass fraction of the product yield is 95%?

Aniline production equation:
C6H5 – NO2 + 3H2 = C6H5 – NH2 + 2H2O.
1) Molar mass of nitrobenzene: 12 * 6 + 1 * 5 + 14 + 2 * 16 = 72 + 5 + 14 + 32 = 123.
2) The amount of nitrobenzene substance: 369/123 = 3 mol.
3) According to the reaction equation, there is one mole of aniline per mole of nitrobenzene. This means that the amount of aniline substance is 3 mol.
4) Molar mass of aniline: 12 * 6 + 1 * 5 + 14 + 1 * 2 = 72 + 5 + 14 + 2 = 93.
5) Theoretical mass of aniline yield: 93 * 3 = 279g.
6) The practical mass of aniline yield: 279 * 95/100 = 265g – the answer.