What mass of aniline can be processed 150 grams of hydrochloric acid with a mass fraction of ash chlorine of 15 percent

univerkov | December 8, 2020 | education

C6H5NH2 + HCl> C6H5Cl + NH3 C6H5NH2 = x HCl = 150 * 15/100 = 22.5 grams M (C6H5NH2) = 93 g / mol M (HCl) = 36.5 g / mol x = 22.5 * 93 / 36.5 = 57.3 grams

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