What mass of barium hydroxide Ba (OH) 2 is required to neutralize a 49g solution containing sulfuric acid?

Barium hydroxide reacts with sulfuric acid. This forms a water-insoluble barium sulfate salt, which precipitates. The reaction is described by the following chemical reaction equation.

Ba (OH) 2 + H2SO4 = BaSO4 + 2H2O;

Barium hydroxide reacts with sulfuric acid in equal molar amounts. In this case, the same amount of insoluble salt is synthesized.

Let’s find the chemical amount of sulfuric acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol; N H2SO4 = 49/98 = 0.5 mol;

The same amount of barium hydroxide will react.

Let’s determine its weight.

M Ba (OH) 2 = 137 + 16 x 2 + 2 = 171 grams / mol; m Ba (OH) 2 = 0.5 x 171 = 85.5 grams;

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