What mass of barium nitrate can be obtained by reacting 20 grams of barium oxide with nitric acid?

BaO + 2HNO3 = Ba (NO3) 2 + H2O – ion exchange, barium nitrate was formed;
Calculations by the formulas of substances:
M (BaO) = 153.3 g / mol;

M Ba (NO3) 2 = 261.3 g / mol.

Determine the amount of oxide:

Y (BaO) = m / M = 20 / 153.3 = 0.13 mol;

Y Ba (NO3) 2 = 0.13 mol since the amount of substances is 1 mol.

Find the mass of salt:

m Ba (NO3) 2 = Y * M = 0.13 * 261.3 = 33.97 g

Answer: obtained barium nitrate weighing 33.97 g