What mass of barium sulfate is formed by the interaction of excess barium chloride and 196 g of sulfuric
| December 10, 2020 | education
What mass of barium sulfate is formed by the interaction of excess barium chloride and 196 g of sulfuric acid solution with a mass fraction of H2SO4 10%.
BaCl2 + H2SO4 = BaSO4 + 2HCl
the mass of the acid itself in solution = 0.1 * 196 = 19.6 grams
n (H2SO4) = m / M = 19.6 / (2 + 32 + 16 * 4) = 0.2 mol
m (BaSO4) = nM = 0.2 * (137 + 32 + 64) = 46.6 grams
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