What mass of barium sulfate is formed when 30.6 g of barium oxide reacts with a sufficient amount of sulfuric acid?

The reaction between sulfuric acid and barium oxide is described by the following chemical reaction equation:

BaO + H2SO4 = BaSO4 + H2O;

Upon the interaction of 1 mol of barium oxide and 1 mol of sulfuric acid, 1 mol of insoluble barium sulfate is synthesized.

Let’s calculate the chemical amount of a substance that is contained in 30.6 grams of barium oxide.

M BaO = 137 + 16 = 153 grams / mol;

N BaO = 30.6 / 153 = 0.2 mol;

The same amount of barium sulfate will be synthesized.

Let’s calculate its weight.

M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol;

m BaSO4 = 233 x 0.2 = 46.6 grams;