What mass of BaSo4 is formed during the interaction of a solution containing BaCl weighing 62.4 g? with an excess of H2So4?

1. To solve the problem, write the equation:
BaCl2 + H2SO4 = BaSO4 + 2HCl – ion exchange, obtained barium sulfate in the sediment;
2. Calculation of molar masses:
M (BaCl2) = 208.3 g / mol;
M (BaSO4) = 233.3 g / mol.
3. Calculate the number of moles of barium chloride, barium sulfate:
Y (BaCl2) = m / M = 62.4 / 208.3 = 0.299 mol;
Y (BaSO4) = 0.299 mol since the amount of these substances is 1 mol according to the equation.
4. Find the mass value for the reaction product:
m (BaSO4) = Y * M = 0.299 * 233.3 = 69.75 g.
Answer: Barium sulfate weighing 69.75 g was obtained during the reaction.