What mass of benzene is required in grams to obtain 246 g of nitrobenzene if its practical yield is 92%?

C6H6 + HNO3 = C6H5NO2 + H2O.
1) Find the theoretical product yield. To do this, we multiply the mass of the theoretical output by one hundred percent and divide by the practical output: 246 * 100/90 = 273.3 g.
2) Molar mass of nitrobenzene: 12 * 6 + 5 * 1 + 14 + 16 * 2 = 123.
3) Amount of nitrobenzene substance: 246/123 = 2 mol.
4) According to the reaction equation, the quantities of nitrobenzene and benzene are 1: 1. This means that the amount of benzene is 2 mol.
5) The molar mass of benzene: 12 * 6 + 1 * 6 = 78.
6) The mass of benzene: 78 * 2 = 156g – the answer.