What mass of calcium carbide is required to obtain 100 g of benzene?

Let’s calculate the molar amount of benzene.

For this purpose, we divide its mass by the weight of 1 mole of the substance.

M C6H6 = 12 x 6 + 6 = 78 grams / mol;

N C6H6 = 100/78 = 1.282 mol;

To get this amount of benzene, you need to take 3 times more acetylene. The molar amount of silicon carbide is equal to the molar amount of acetylene.

Acetylene is synthesized by the interaction of calcium carbide with water.

CaC2 + 2H2O = Ca (OH) 2 + C2H2 ↑;

Let’s calculate the weight of silicon carbide.

To do this, we multiply the amount of a substance by the weight of 1 mole of a substance, which is equal to the sum of the molar weights of the elements that make up this molecule.

M CaC2 = 40 + 12 x 2 = 64 grams / mol;

The weight of pure silicon carbide will be:

m CaC2 = 1.282 x 3 x 64 = 246.144 grams;