What mass of calcium carbide is required to obtain 1m3 of acetylene, if acetylene is 60% in comparison

What mass of calcium carbide is required to obtain 1m3 of acetylene, if acetylene is 60% in comparison with theoretically possible?

The reaction for the synthesis of acetylene from calcium carbide is described by the following chemical reaction equation:

CaC2 + 2H2O = C2H2 + Ca (OH) 2;

From 1 mole of calcium carbide, 1 mole of acetylene is synthesized.

Let’s calculate the available chemical amount of the acetylene substance.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

N C2H2 = 1000 / 22.4 = 44.64 mol;

Taking into account the yield of 60% for this reaction, it is necessary to take 44.64 / 0.6 = 74.4 mol of silicon carbide.

Let’s calculate its weight.

M CaC2 = 40 + 12 x 2 = 64 grams / mol;

m CaC2 = 74.4 x 64 = 4.762 grams = 4.76 kg;