What mass of calcium carbonate is formed by the interaction of 21.2 grams of sodium carbonate

| August 22, 2021 | education

What mass of calcium carbonate is formed by the interaction of 21.2 grams of sodium carbonate with a solution of calcium hydroxide?

To solve this problem, we write down the given: m (Na2CO3) = 21, 2 g the substance reacted with calcium hydroxide (Ca (OH) 2).
You need to determine the mass of calcium carbonate (CaCO3), which was formed as a result of the reaction.
Solution:
Let us write the reaction equation
Na2CO3 + Ca (OH) 2 = CaCO3 + NaOH
Let’s arrange the coefficients and get:
Na2CO3 + Ca (OH) 2 = CaCO3 + 2NaOH.
Over sodium carbonate (Na2CO3) we sign 21.2 g, and over calcium carbonate (CaCO3) – x g.
Calculate the molar masses: sodium carbonate and calcium carbonate
M (Na2CO3) = 23 * 2 + 12 + 16 * 3 = 106 g / mol
M (CaCO3) = 40 + 12 + 16 * 3 = 100 g / mol.
Let’s make the proportion and find x.
x = 21.2 * 100/106 = 20 g.
Answer: m (CaCO3) = 20 g.



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