What mass of calcium carbonate is formed by the interaction of an excess of calcium nitrate solution and 250 g

univerkov | November 22, 2020 | education

What mass of calcium carbonate is formed by the interaction of an excess of calcium nitrate solution and 250 g of a solution containing 20% sodium carbonate?

Ca (NO3) 2 + Na2CO3 = CaCO3 + 2NaNO3
m substance (Na2CO3) = 20% * 250g / 100 = 50g
n (Na2CO3) = m / M = 50g / 106g / mol = 0.471 mol
n (CaCO3) = n (Na2CO3) = 0.471 mol
m (CaCO3) = n * M = 0.471 mol * 100 = 47.1 g

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