What mass of calcium carbonate is formed by the interaction of carbon monoxide (IV)

univerkov | September 4, 2021 | education

What mass of calcium carbonate is formed by the interaction of carbon monoxide (IV) weighing 17.6 grams with a solution of calcium hydroxide?

CO2 + Ca (OH) 2 = CaCO3 + H2O.
1) According to the periodic table, we calculate the molar mass of carbon dioxide: 12 + 16 * 2 = 44.
2) Find the amount of substance carbon dioxide. For this, the mass of the gas is divided by its molar mass: 17.6 / 44 = 0.4 mol.
3) According to the reaction equation, there is one mole of calcium carbonate for one mole of carbon dioxide. This means that the amount of carbonate substance is 0.4 mol.
4) Calculate the molar mass of calcium carbonate: 40 + 12 + 16 * 3 = 100.
5) Find the mass of calcium carbonate: 100 * 0.4 = 40g – the answer.

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