What mass of calcium hydroxide is needed to react with hydrochloric acid to obtain 0.2 mol of calcium chloride?

univerkov | January 17, 2021 | education

Given:
n (CaCl2) = 0.2 mol
To find:
m (Ca (OH) 2)
Decision:
Ca (OH) 2 + 2HCl = CaCl2 + 2H2O
n (CaCl2): n (Ca (OH) 2) = 1: 1
n (Ca (OH) 2) = 0.2 mol
m (Ca (OH) 2) = n * M = 0.2 mol * 74 g / mol = 14.8 g
Answer: 14.8 g

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