What mass of calcium hydroxide should be taken to neutralize 30 g of acetic acid solution

What mass of calcium hydroxide should be taken to neutralize 30 g of acetic acid solution with a mass fraction of 20% acid?

1. Let’s write down the reaction equation:

2CH3COOH + Ca (OH) 2 = 2H2O + (CH3COO) 2Ca.

2. Find the mass of the acid in the solution and convert it to the amount:

m (CH3COOH) = (m (solution) * ω (CH3COOH)) / 100% = (30 g * 20%) / 100% = 6 g.

n (CH3COOH) = m (CH3COOH) / M (CH3COOH) = 6 g / 60 g / mol = 0.1 mol.

3. Using the equation, we find the amount of calcium hydroxide and convert it to the amount:

n (Ca (OH) 2) = n (CH3COOH) = 0.1 mol.

m (Ca (OH) 2) = n (Ca (OH) 2) * M (Ca (OH) 2) = 0.1 mol * 74 g / mol = 7.4 g.

Answer: 7.4 g.