What mass of calcium is required for the reaction with oxygen of 22.4 liters according

What mass of calcium is required for the reaction with oxygen of 22.4 liters according to the reaction equation 2 Ca + O2 = 2 CaO.

Calcium enters into an oxidation reaction with oxygen. This reaction is described by the following equation:

Ca + ½ O2 = CaO;

During oxidation, one oxygen atom is attached to the calcium atom. In this case, one molecule of calcium oxide is synthesized.

Let’s define the chemical (molar) amount of oxygen.

Divide the available volume of oxygen by the volume of 1 mole of gas (22.4 liters).

N O2 = 22.4 / 22.4 = 1 mol;

In this reaction, 2 times more calcium will react with oxygen.

Let’s determine its weight.

N Ca = 1 x 2 = 2 mol; M Ca = 40 grams / mol; m Ca = 2 x 40 = 80 grams;