What mass of calcium oxide and what volume of carbon dioxide can be obtained by decomposition

What mass of calcium oxide and what volume of carbon dioxide can be obtained by decomposition of Ca Co3 m = 250 grams?

The decomposition reaction of calcium carbonate occurs in accordance with the following chemical reaction equation:

CaCO3 = CaO + CO2;

From 1 mole of calcium carbonate, 1 mole of calcium oxide and 1 mole of carbon dioxide are formed.

Let’s determine the chemical amount of a substance in 250 grams of calcium carbonate.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 250/100 = 2.5 mol;

Let’s calculate the mass of 2.5 mol of calcium oxide.

M CaO = 40 + 16 = 56 grams / mol;

m CaO = 56 x 2.5 = 140 grams;

Let’s calculate the volume of 2.5 mol of carbon dioxide.

One mole of gas under normal conditions fills a volume of 22.4 liters.

The volume of carbon dioxide will be equal to:

V CO2 = 2.5 x 22.4 = 56 liters;