What mass of calcium oxide can be obtained by decomposition of 300 g of limestone (CaCO3)

What mass of calcium oxide can be obtained by decomposition of 300 g of limestone (CaCO3), if it is known that the yield of this reaction is 70%.

CaCO3 = CaO + CO2
n (CaCO3) = m \ M = 300 \ 100 = 3 mol
for ur-th p-and n (CaCO3) = n (CaO) = 3 mol
m (CaO) theory = nM = 3 * 56 = 168 g
output = m (practice) \ m (theory)
hence m (practical) = output * m (theory) = 0.7 * 168 = 117.6 g
Answer: 117.6 g