What mass of calcium oxide can be obtained from 250 kg of limestone, in which the mass fraction of impurities is 0.2.

The decomposition reaction of limestone is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

When 1 mol of limestone is decomposed, 1 mol of gaseous carbon dioxide is synthesized.

This also synthesizes 1 mol of calcium oxide

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 250,000 x 0.8 / 100 = 2,000 mol;

During the reaction, the same amount of calcium oxide will be synthesized.

N CaO = 2000 mol;

Its weight will be:

M CaO = 40 + 16 = 56 grams / mol;

m CaO = 56 x 2,000 = 112,000 grams = 112 kg;

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