What mass of calcium oxide is formed by calcining 600 g of calcium carbonate containing 20%

| March 23, 2021 | education

What mass of calcium oxide is formed by calcining 600 g of calcium carbonate containing 20% impurities (impurities do not enter into the reaction)?

1. Let’s compose the reaction equation reflecting the process of calcining calcium carbonate:

CaCO3 = CaO + CO2 ↑;

2. Determine the mass of pure carbonate:

m (CaCO3) = m (limestone) – m (impurities);

m (impurities) = w (impurities) * m (limestone) = 0.2 * 600 = 120 g;

m (CaCO3) = 600 – 120 = 480 g;

3. Calculate the chemical amount of carbonate:

n (CaCO3) = m (CaCO3): M (CaCO3);

M (CaCO3) = 40 + 12 + 3 * 16 = 100 g / mol;

n (CaCO3) = 480: 100 = 4.8 mol;

4. Set the amount of calcium oxide obtained:

n (CaO) = n (CaCO3) = 4.8 mol;

5. Find the mass of the oxide:

m (CaO) = n (CaO) * M (CaO);

M (CaO) = 40 + 16 = 56 g / mol;

m (CaO) = 4.8 * 56 = 268.8 g.

Answer: 268.8 g.



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