What mass of calcium oxide is formed by the reaction of 5.6 liters of oxygen with the required amount of calcium
| April 19, 2021 | education
2Ca + O2 = 2CaO.
Let’s determine the amount of oxygen.
n = 5.6 / 22.4 = 0.25 mol.
0.25 mol O2 – x mol CaO.
1 mol O2 – 2 mol CaO.
X = 0.25 * 2: 1 = 0.5 mol.
M (CaO) = 56 g / mol.
m (CaO) = 56 * 0.5 = 28 g.
Answer: the mass of calcium oxide is 28 g.
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