What mass of calcium oxide is formed during the decomposition of 980 g of calcium carbonate?

The decomposition reaction of limestone is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

The decomposition of 1 mol of limestone synthesizes 1 mol of gaseous carbon dioxide.

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 980/100 = 9.8 mol;

This amount of calcium oxide will be synthesized.

We calculate the weight of 9.8 mol of calcium oxide. To do this, we multiply the amount of the substance by its molar weight.

M CaO = 40 + 16 = 56 grams / mol;

m CaO = 56 x 9.8 = 548.8 grams;

The weight of calcium oxide will be 548.8 grams.