What mass of calcium sulfate is formed when 9.8 g of sulfate acid reacts with a sufficient amount of calcium oxide?

univerkov | July 5, 2021 | education

1. Let’s write down the reaction equation:

CaO + H2SO4 = CaSO4 + H2O.

2. Find the amount of sulfuric acid:

n (H2SO4) = m (H2SO4) / M (H2SO4) = 9.8 g / 98 g / mol = 0.1 mol.

3. According to the reaction equation, we find the amount and then the mass of calcium sulfate:

n (CaSO4) = n (H2SO4) = 0.1 mol.

m (CaSO4) = n (CaSO4) * M (CaSO4) = 0.1 mol * 136 g / mol = 13.6 g.

Answer: m (CaSO4) = 13.6 g.

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