What mass of CaO can be obtained by decomposition of 500 g of limestone (CaCO3) containing 10% of impurities.

caco3 = cao + co2
let’s make a proportion
500 g-100%
x g-90%
x = 450g
find the amount of calcium carbonate substance
n = 450/100 = 4.5 mol
since the coefficients are the same then the amount of substance in substances is the same
find the mass of calcium oxide
m = 4.5 * 56 = 256g



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