What mass of carbon dioxide is produced by the combustion of 240 g of coal containing 10% impurity?

To solve the problem, we first calculate the mass of pure coal in the sample.

240 * 10% = 24 g. Impurities.

240 – 24 = 216 g of coal, weighed.

The reaction equation looks like this:

C + O2 = CO2

Molar mass of coal = 12 g / mol; molar mass of carbon dioxide = 44 g / mol

To solve the problem, let’s compose the proportion:

216 g of coal corresponds to X g of carbon dioxide as

12 g / mol of coal corresponds to 44 g / mol of carbon dioxide

X = (216 * 44) / 12 = 792 g. Of carbon dioxide.

Answer: 792 g of carbon dioxide is formed.