What mass of carbon dioxide is produced by the decomposition of 150 g of calcium carbonate? (CaCO3)

The limestone decomposition reaction is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

The decomposition of 1 mol of limestone synthesizes 1 mol of gaseous carbon dioxide.

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 150/100 = 1.5 mol;

This amount of carbon dioxide will be synthesized.

Let’s calculate the weight of carbon dioxide.

M CO2 = 12 + 16 x 2 = 44 grams / mol;

m CO2 = 1.5 x 44 = 66 grams;