What mass of carbon dioxide will be released when sodium carbonate weighing 21.2 grams

What mass of carbon dioxide will be released when sodium carbonate weighing 21.2 grams interacts with an excess of hydrochloric acid solution?

1. Let’s compose the equation of interaction of sodium carbonate with an excess of hydrochloric acid:

Na2CO3 + 2HCl = 2NaCl + H2O + CO2 ↑;

2.Calculate the chemical amount of sodium carbonate:

n (Na2CO3) = m (Na2CO3): M (Na2CO3);

M (Na2CO3) = 2 * 23 + 12 + 3 * 16 = 106 g / mol;

n (Na2CO3) = 21.2: 106 = 0.2 mol;

3.According to the reaction equation, the amounts of sodium carbonate and emitted carbon dioxide are the same:

n (CO2) = n (Na2CO3) = 0.2 mol;

4.Calculate the mass of the released gas:

m (CO2) = n (CO2) * M (CO2);

M (CO2) = 12 + 2 * 16 = 44 g / mol;

m (CO2) = 0.2 * 44 = 8.8 g.

Answer: 8.8 g.