# What mass of carbon is required to produce methane in reaction with 10 liters of hydrogen?

1) Getting methane: CH4 = C + 2H2.

2) The amount of substance H2: νH2 = VH2 / Vm, where VH2 is the volume of reacted hydrogen (VH2 = 10 l); Vm – molar volume (const, Vm = 22.4 l / mol).

Calculation: νH2 = VH2 / Vm = 10 / 22.4 ≈ 0.4464 mol.

3) The ratio of the amount of substance: νС / νН2 = 1/2, whence we express: νС = νН2 / 2.

Calculation: νС = νН2 / 2 = 0.4464 / 2 = 0.2232 mol.

4) Required mass of carbon: mC = MC * νС, where MC is the molar mass of carbon (const, MC = 12 g / mol).

Calculation: mC = MC * νC = 12 * 0.2232 ≈ 2.68 g.

Answer: To obtain 10 liters of hydrogen, 2.68 g of carbon are needed.

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