What mass of charcoal contains. 96% of carbon will be required for the complete reduction of iron (III) oxide weighing 100 g?

1. Let’s write the reaction equation:
2Fe2O3 + 3C = 4Fe + 3CO2.
2. Find the amount of iron oxide:
n (Fe2O3) = m (Fe2O3) / M (Fe2O3) = 100 g / 160 g / mol = 0.625 mol.
3. Using the reaction equation, we find the amount, and then the mass of carbon:
3n (C) = 2n (Fe2O3)
n (C) = 2 / 3n (Fe2O3) = 2/3 * 0.625 mol = 0.42 mol.
m (C) = n (C) * M (C) = 0.42 mol * 12 g / mol = 5.04 g.
4. Find the mass of charcoal:
m (coal) = m (C) * 100% / ω (C) = 5.04 g * 100% / 96% = 5.25 g.
Answer: m (coal) = 5.25 g.