What mass of chloride is formed if caustic soda weighing 30 g is added to a 20% solution of hydrochloric acid weighing 25 g?

1. The interaction of hydrochloric acid with caustic soda proceeds according to the reaction equation:

HCl + NaOH = NaCl + H2O;

2.Calculate the mass of hydrogen chloride:

m (HCl) = w (HCl) * m (acid) = 0.2 * 25 = 5 g;

3.Calculate the chemical amount of hydrogen chloride:

n (HCl) = m (HCl): M (HCl) = 5: 36.5 = 0.137 mol;

4. find the amount of sodium hydroxide:

n (NaOH) = m (NaOH): M (NaOH) = 30:40 = 0.75 mol;

5.the deficiency is hydrochloric acid, we determine the amount of sodium chloride by the deficiency:

n (NaCl) = n (HCl) = 0.137 mol;

6.Calculate the mass of the formed chloride:

m (NaCl) = n (NaCl) * M (NaCl) = 0.137 * 58.5 = 8 g.

Answer: 8 g.



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