What mass of copper can be obtained as a result of the interaction between copper oxide (2) and 5.6 liters of hydrogen?

The reduction reaction of copper oxide with hydrogen occurs in accordance with the following chemical reaction equation:

CuO + H2 = Cu + H2O;

1 mole of copper oxide reacts with 1 mole of hydrogen. This forms one mole of metallic copper and 1 mole of water.

Let’s calculate the chemical amount of a substance contained in 5.6 liters of hydrogen.

One mole of gas under normal conditions fills a volume of 22.4 liters.

N H2 = 5.6 / 22.4 = 0.25 mol;

The same amount of copper will be obtained. Let’s define its mass.

M Cu = 64 grams / mol;

m Cu = 64 x 0.25 = 16 grams;