What mass of copper can be obtained by reacting 120 g of copper oxide (2) with carbon monoxide (2) at a yield of 90%?

The reduction reaction of copper oxide is described by the following chemical reaction equation.

CuO + CO = Cu + CO2;

1 mole of metal oxide reacts with 1 mole of carbon monoxide. This synthesizes 1 mole of metal and 1 mole of carbon dioxide.

Let’s calculate the chemical amount of a substance in 120 grams of metal oxide.

M CuO = 64 + 16 = 80 grams / mol;

N CuO = 120/80 = 1.5 mol;

From this amount, taking into account the yield of 90%, it is possible to obtain 1.5 x 0.9 = 1.35 mol of metal.

Let’s calculate its mass.

M Cu = 64 grams / mol;

The mass of copper is:

m Cu = 64 x 1.35 = 86.4 grams;