What mass of copper can be obtained by reducing 160 g of copper (II) oxide with coal

What mass of copper can be obtained by reducing 160 g of copper (II) oxide with coal, if the mass fraction of the copper yield is 85%?

The reduction reaction of copper oxide is described by the following chemical reaction equation.

CuO + CO = Cu + CO2;

1 mole of metal oxide reacts with 1 mole of carbon monoxide. This synthesizes 1 mole of metal and 1 mole of carbon dioxide.

Let’s calculate the chemical amount of a substance in 160 grams of metal oxide.

M CuO = 64 + 16 = 80 grams / mol;

N CuO = 160/80 = 2 mol;

From this amount, taking into account the yield of 85%, it is possible to obtain 2.0 x 0.85 = 1.7 mol of metal.

Let’s calculate its mass.

M Cu = 64 grams / mol;

The mass of copper is:

m Cu = 64 x 1.7 = 108.8 grams;