What mass of copper can be obtained by reducing 160 g of copper (II) oxide with coal, if the mass fraction of the copper yield is 85%?
The reduction reaction of copper oxide is described by the following chemical reaction equation.
CuO + CO = Cu + CO2;
1 mole of metal oxide reacts with 1 mole of carbon monoxide. This synthesizes 1 mole of metal and 1 mole of carbon dioxide.
Let’s calculate the chemical amount of a substance in 160 grams of metal oxide.
M CuO = 64 + 16 = 80 grams / mol;
N CuO = 160/80 = 2 mol;
From this amount, taking into account the yield of 85%, it is possible to obtain 2.0 x 0.85 = 1.7 mol of metal.
Let’s calculate its mass.
M Cu = 64 grams / mol;
The mass of copper is:
m Cu = 64 x 1.7 = 108.8 grams;
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