What mass of copper can be reduced from CuO with hydrogen obtained as a result of the reaction

What mass of copper can be reduced from CuO with hydrogen obtained as a result of the reaction of sodium with 12.04 grams of ethanol solution with W = 95.5%?

Based on the data, we write down the equation of the processes:

2C2H5OH + 2Na = 2C2H5ONa + H2 – substitutions, hydrogen is evolved;
CuO + H2 = Cu + H2O – reduction, hydrogen is formed.
Calculations by formulas:
M (C2H5OH) = 46 g / mol;

M (H2) = 2 g / mol;

M (Cu) = 63.5 g / mol.

4. Determine the mass, the amount of alcohol:

m (C2H5OH) = 12.04 / 0.955 = 12.6 g (theoretical weight);

Y (C2H5OH) = m / M = 12.6 / 46 = 0.27 mol.

Proportions:
0.27 mol (C2H5OH) – X mol (H2);

-2 mol – 1 mol from here, X mol (H2) = 0.2 * 1/2 = 0.1 mol;

V (H2) = 0.1 * 22.4 = 2.24 L

Y (Cu) = 0.1 mol as well as hydrogen, since the amount of substances is 1 mol.

Find the mass of the metal:
m (Cu) = Y * M = 0.1 * 63.5 = 6.35 g

Answer: received copper weighing 6.35 g