What mass of copper (II) oxide can be reduced by hydrogen released during the reaction of 5.6 g

What mass of copper (II) oxide can be reduced by hydrogen released during the reaction of 5.6 g of zinc with hydrochloric acid?

Find the molar amount of hydrogen hydrogen. It will be equal to the chemical amount of dissolved zinc:

Zn + 2HCl → ZnCl2 + H2;

Let’s calculate the molar amount of zinc.

M Zn = 65 grams / mol;

N Zn = 5.6 / 65 = 0.086 mol;

Reduction of copper oxide is described by the following equation:

CuO + H2 = Cu + H2O;

Therefore, 0.086 mol of hydrogen can be used to reduce 0.086 mol of cupric oxide.

Determine the weight of 0.086 mol of copper oxide.

M CuO = 64 + 16 = 80 grams / mol;

m CuO = 80 x 0.086 = 6.88 grams;