What mass of copper (II) sulfide is formed as a precipitate when hydrogen

| April 8, 2021 | education

What mass of copper (II) sulfide is formed as a precipitate when hydrogen sulfide is passed through 200 g of a 16% solution of copper (II) sulfate?

Find the mass of copper sulfate in solution.

W = m (substance): m (solution) × 100%,

m (substance) = (m (solution) × W): 100%.

m (CuSO4) = (200 g × 16%): 100% = 32 g.

Let’s find the amount of substance CuSO4 by the formula:

n = m: M.

M (CuSO4) = 160 g / mol.

n = 32 g: 160 g / mol = 0.2 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

CuSO4 + H2S = CuS ↓ + H2SO4.

According to the reaction equation, there is 1 mol of CuS per 1 mol of CuSO4. Substances are in quantitative ratios 1: 1.

n (CuS) = n (CuSO4) = 0.2 mol.

Let’s find the mass of CuS by the formula:

m = n × M,

M (CuS) = 96 g / mol.

m = 0.2 mol × 96 g / mol = 19.2 g.

Answer: 19.2 g.



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