What mass of copper is required for the formation of 84 g of copper (II) oxide during its oxidation with oxygen?

Given:
m (CuO) = 84 g

Find:
m (Cu) -?

1) 2Cu + O2 => 2CuO;
2) n (CuO) = m / M = 84/80 = 1.1 mol;
3) n (Cu) = n (CuO) = 1.1 mol;
4) m (Cu) = n * M = 1.1 * 64 = 70 g.

Answer: The mass of Cu is 70 g.



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